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Fire fighter had an accident leads to injury in his thigh, caused fracture in 20 points his femur (consider it has cylindrical shape). Due to this injury, the shorting in this bone (change in the length failure) is 0.08 mm. Calculate the length of the bone after injury with taking into consideration that the applied force was 500 N, and the radius of his bone is 2 cm with the cross section equal to 0.00125 m2, (Young’s modulus = 1.5 X 109 N/m2) Note: answer the question on the side paper and choose the result from the form as number only with its units

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